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6a^2+5a-6=0
a = 6; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·6·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-13}{2*6}=\frac{-18}{12} =-1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+13}{2*6}=\frac{8}{12} =2/3 $
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